Find Numbers with Even Number of Digits

Given an array nums of integers, return how many of them contain an even number of digits.
 

Example 1:

Input: nums = [12,345,2,6,7896]
Output: 2
Explanation: 
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.

Example 2:

Input: nums = [555,901,482,1771]
Output: 1 
Explanation: 
Only 1771 contains an even number of digits.

 

Constraints:


Solution:

class Solution {
    public int findNumbers(int[] nums) {
        int num = 0;
        for (int n : nums) {
            if (String.valueOf(n).length() % 2 == 0) {
                num ++;
            }
        }
        return num;
    }
}