There is a room with n bulbs, numbered from 0 to n-1, arranged in a row from left to right. Initially all the bulbs are turned off.
Your task is to obtain the configuration represented by target where target[i] is '1' if the i-th bulb is turned on and is '0' if it is turned off.
You have a switch to flip the state of the bulb, a flip operation is defined as follows:
Choose any bulb (index i) of your current configuration.
Flip each bulb from index i to n-1.
When any bulb is flipped it means that if it is 0 it changes to 1 and if it is 1 it changes to 0.
Return the minimum number of flips required to form target.
Example 1:
Input: target = "10111"
Output: 3
Explanation: Initial configuration "00000".
flip from the third bulb: "00000" -> "00111"
flip from the first bulb: "00111" -> "11000"
flip from the second bulb: "11000" -> "10111"
We need at least 3 flip operations to form target.
class Solution {
public int minFlips(String target) {
int count = 0;
for (int i = 0; i < target.length(); i ++) {
char c = target.charAt(i);
if (count % 2 == 0 && c == '1' || count % 2 == 1 && c == '0') {
count ++;
}
}
return count;
}
}