There is a special keyboard with all keys in a single row.
Given a string keyboard of length 26 indicating the layout of the keyboard (indexed from 0 to 25), initially your finger is at index 0. To type a character, you have to move your finger to the index of the desired character. The time taken to move your finger from index i to index j is |i - j|.
You want to type a string word. Write a function to calculate how much time it takes to type it with one finger.
Example 1:
Input: keyboard = "abcdefghijklmnopqrstuvwxyz", word = "cba"
Output: 4
Explanation: The index moves from 0 to 2 to write 'c' then to 1 to write 'b' then to 0 again to write 'a'.
Total time = 2 + 1 + 1 = 4.
Example 2:
Input: keyboard = "pqrstuvwxyzabcdefghijklmno", word = "leetcode"
Output: 73
Constraints:
keyboard.length == 26
keyboard contains each English lowercase letter exactly once in some order.
1 <= word.length <= 10^4
word[i] is an English lowercase letter.
Solution:
class Solution {
public int calculateTime(String keyboard, String word) {
int[] map = new int[26];
for (int i = 0; i < keyboard.length(); i ++) {
map[keyboard.charAt(i) - 'a'] = i;
}
int prev = 0, sum = 0;
for (char c : word.toCharArray()) {
int index = map[c - 'a'];
sum += Math.abs(prev - index);
prev = index;
}
return sum;
}
}