Day of the Year
Given a string date representing a
Gregorian calendar date formatted as YYYY-MM-DD, return the day number of the year.
Example 1:
Input: date = "2019-01-09"
Output: 9
Explanation: Given date is the 9th day of the year in 2019.
Example 2:
Input: date = "2019-02-10"
Output: 41
Example 3:
Input: date = "2003-03-01"
Output: 60
Example 4:
Input: date = "2004-03-01"
Output: 61
Constraints:
- date.length == 10
- date[4] == date[7] == '-', and all other date[i]'s are digits
- date represents a calendar date between Jan 1st, 1900 and Dec 31, 2019.
Solution:
class Solution {
public int dayOfYear(String date) {
Map<Integer, Integer> monthToDays = new HashMap();
monthToDays.put(1, 31);
monthToDays.put(2, 28);
monthToDays.put(3, 31);
monthToDays.put(4, 30);
monthToDays.put(5, 31);
monthToDays.put(6, 30);
monthToDays.put(7, 31);
monthToDays.put(8, 31);
monthToDays.put(9, 30);
monthToDays.put(10, 31);
monthToDays.put(11, 30);
monthToDays.put(12, 31);
String[] arr = date.split("-");
int year = Integer.parseInt(arr[0]);
int month = Integer.parseInt(arr[1]);
int day = Integer.parseInt(arr[2]);
if (year % 4 == 0 && (year % 100 != 0 || year % 400 == 0)) {
monthToDays.put(2, 29);
}
int d = 0;
for (int i = 1; i < month; i ++) {
d += monthToDays.get(i);
}
d += day;
return d;
}
}