You are given an m x n matrix M initialized with all 0's and an array of operations ops, where ops[i] = [ai, bi] means M[x][y] should be incremented by one for all 0 <= x < ai and 0 <= y < bi.
Count and return the number of maximum integers in the matrix after performing all the operations.
Example 1:
Input: m = 3, n = 3, ops = [[2,2],[3,3]]
Output: 4
Explanation: The maximum integer in M is 2, and there are four of it in M. So return 4.
Example 2:
Input: m = 3, n = 3, ops = [[2,2],[3,3],[3,3],[3,3],[2,2],[3,3],[3,3],[3,3],[2,2],[3,3],[3,3],[3,3]]
Output: 4
Example 3:
Input: m = 3, n = 3, ops = []
Output: 9
Constraints:
1 <= m, n <= 4 * 104
1 <= ops.length <= 104
ops[i].length == 2
1 <= ai <= m
1 <= bi <= n
Solution:
class Solution {
public int maxCount(int m, int n, int[][] ops) {
int minRow = m, minCol = n;
for (int[] op : ops) {
minRow = Math.min(op[0], minRow);
minCol = Math.min(op[1], minCol);
}
return minRow * minCol;
}
}