# Reformat Date

Given a date string in the form Day Month Year, where:

• Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
• Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
• Year is in the range [1900, 2100].
Convert the date string to the format YYYY-MM-DD, where:

• YYYY denotes the 4 digit year.
• MM denotes the 2 digit month.
• DD denotes the 2 digit day.

Example 1:

```Input: date = "20th Oct 2052"
Output: "2052-10-20"
```
Example 2:

```Input: date = "6th Jun 1933"
Output: "1933-06-06"
```
Example 3:

```Input: date = "26th May 1960"
Output: "1960-05-26"
```

Constraints:

• The given dates are guaranteed to be valid, so no error handling is necessary.

Solution:

```class Solution {
public String reformatDate(String date) {
Map<String, String> map = new HashMap();
map.put("Jan", "01");
map.put("Feb", "02");
map.put("Mar", "03");
map.put("Apr", "04");
map.put("May", "05");
map.put("Jun", "06");
map.put("Jul", "07");
map.put("Aug", "08");
map.put("Sep", "09");
map.put("Oct", "10");
map.put("Nov", "11");
map.put("Dec", "12");
String[] arr = date.split(" ");
StringBuilder sb = new StringBuilder();
sb.append(arr[2]);
sb.append("-");
sb.append(map.get(arr[1]));
sb.append("-");
String day = arr[0].replaceAll("[\\D]", "");
if (day.length() == 1) day = "0" + day;
sb.append(day);
return sb.toString();
}
}```