Reorder Data in Log Files

You have an array of logs.  Each log is a space delimited string of words.

For each log, the first word in each log is an alphanumeric identifier.  Then, either:

We will call these two varieties of logs letter-logs and digit-logs.  It is guaranteed that each log has at least one word after its identifier.

Reorder the logs so that all of the letter-logs come before any digit-log.  The letter-logs are ordered lexicographically ignoring identifier, with the identifier used in case of ties.  The digit-logs should be put in their original order.

Return the final order of the logs.

 

Example 1:

Input: logs = ["dig1 8 1 5 1","let1 art can","dig2 3 6","let2 own kit dig","let3 art zero"]
Output: ["let1 art can","let3 art zero","let2 own kit dig","dig1 8 1 5 1","dig2 3 6"]
 

Constraints:

  1. 0 <= logs.length <= 100
  2. 3 <= logs[i].length <= 100
  3. logs[i] is guaranteed to have an identifier, and a word after the identifier.
Solution:

class Solution {
    public String[] reorderLogFiles(String[] logs) {
        List<String> dLogs = new ArrayList<>();
        PriorityQueue<String> lLogs = new PriorityQueue<String>((a, b) -> {
            String[] aArr = a.split(" ");
            String[] bArr = b.split(" ");
            String aLog = String.join(" ", Arrays.copyOfRange(aArr, 1, aArr.length));
            String bLog = String.join(" ", Arrays.copyOfRange(bArr, 1, bArr.length));
            if (aLog.compareTo(bLog) == 0) {
                return aArr[0].compareTo(bArr[0]);
            }
            return aLog.compareTo(bLog);
        });
        for (String log : logs) {
            String w = log.split(" ")[1];
            boolean isDigit = true;
            for (char c : w.toCharArray()) {
                if (!Character.isDigit(c)) {
                    isDigit = false;
                }
            }
            if (isDigit) {
                dLogs.add(log);
            } else {
                lLogs.offer(log);
            }
        }
        String[] result = new String[logs.length];
        int i = 0;
        while (!lLogs.isEmpty()) {
            result[i ++] = lLogs.poll();
        }
        for (String dLog : dLogs) {
            result[i ++] = dLog;
        }
        return result;
    }
}