Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.
Example: Given a binary tree
1
/ \
2 3
/ \
4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
Note: The length of path between two nodes is represented by the number of edges between them.
Solution:
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public int diameterOfBinaryTree(TreeNode root) {
if (root == null) return 0;
int[] max = new int[]{0};
helper(root, max);
return max[0] - 1;
}
private int helper(TreeNode root, int[] max) {
if (root == null) return 0;
int left = helper(root.left, max);
int right = helper(root.right, max);
max[0] = Math.max(max[0], left + 1 + right);
return Math.max(left, right) + 1;
}
}